(8x^2+5x)=(2x^2-2)

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Solution for (8x^2+5x)=(2x^2-2) equation: 



(8x^2+5x)=(2x^2-2)

We move all terms to the left:

(8x^2+5x)-((2x^2-2))=0

We get rid of parentheses

8x^2+5x-((2x^2-2))=0



We calculate terms in parentheses: -((2x^2-2)), so:

(2x^2-2)

We get rid of parentheses

2x^2-2

Back to the equation:

-(2x^2-2)



We get rid of parentheses

8x^2-2x^2+5x+2=0

We add all the numbers together, and all the variables

6x^2+5x+2=0

a = 6; b = 5; c = +2;
Δ = b2-4ac
Δ = 52-4·6·2
Δ = -23
Delta is less than zero, so there is no solution for the equation

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